A horse travels the same distance every day.

Oddly, two of its legs travel 30 miles each day and the other two legs travel nearly 31 miles.

It would seem that two of the horse's legs must be one mile ahead of the other two legs, but of course this can't be true.

Since the horse is normal, how is this situation possible?

Subscribe to:
Post Comments (Atom)

the horse walks in a circle. I'll leave it up to my math wiz bro to say how tight the circle is...

ReplyDeleteOK, does the horse end up at the same place it begins? And does it visit any places twice along the way? How far apart are the horse's left and right legs?Assuming the answers are yes, yes, and 2 feet, respectively, then the horse has probably made about 420 laps around a circular track with a 60 foot radius.

ReplyDeleteIam going to say that the horse runs practice on a track all day. Simmilar in how a car needs a rear differential because the inner wheels don't travel as far as the outer wheels.

ReplyDeleteYou all hit it on the head. I never gave enough information to actually calculate the radius of the circle, but I'll take jonathan's word that his numbers make sense given his assumptions. ;-)

ReplyDeleteJonathan deserves bonus points.

ReplyDeleteI wish I had bonus points to give. But I guess he'll have to settle for a link to his site from mine.

ReplyDeleteWe are not talking about the same horse

ReplyDelete