I'm posting one puzzle, riddle, math, or statistical problem a day. Try to answer each one and post your answers in the comments section. I'll post the answer the next day. Even if you have the same answer as someone else, feel free to put up your answer, too!
mike, are you telling me that (x-a)*(x-b)*(x-c)*(x-d)*...*(x-z) is zero, where a-z are integers and x is a variable? because if you are, you're crazy...please explain.
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-(a + b + c... + w + y + z)?
ReplyDeleteAnd Mike, if something does not have a name how do you talk about it?
You say study of picture of postcards, of course! ;-)
ReplyDeleteBut to be serious for a second, I was surprised to find out there was a study of picture postcards, nevermind there is a name for the study.
You say study of picture of postcards, of course! ;-)
ReplyDeleteBut to be serious for a second, I was surprised to find out there was a study of picture postcards, nevermind there is a name for the study.
Blogger can be such a pain. Sorry about the double post.
ReplyDeleteAnswer to products: Zero. All factors are multiplied by the factor (x-x) which is zero.
mike,
ReplyDeleteare you telling me that (x-a)*(x-b)*(x-c)*(x-d)*...*(x-z) is zero, where a-z are integers and x is a variable? because if you are, you're crazy...please explain.
oh...right. the variable "x" is the same as the letter "x". mathematically horrendous, but cute.
ReplyDeleteIf each expression is multiplied, then there should not be commas between them.
ReplyDelete(x-a), (x-b) is not equal to
(x-a)(x-b)
The way I wrote it was a series, not as the product. I believe it's stated correctly. Of course, I have been known to make mistakes before!
ReplyDelete