tag:blogger.com,1999:blog-15628310.post116100273271732014..comments2020-06-29T12:19:43.336-04:00Comments on Question of the day: ProductsAnonymoushttp://www.blogger.com/profile/18153935609499338685noreply@blogger.comBlogger8125tag:blogger.com,1999:blog-15628310.post-1163813596702327102006-11-17T20:33:00.000-05:002006-11-17T20:33:00.000-05:00The way I wrote it was a series, not as the produc...The way I wrote it was a series, not as the product. I believe it's stated correctly. Of course, I have been known to make mistakes before!Anonymoushttps://www.blogger.com/profile/18153935609499338685noreply@blogger.comtag:blogger.com,1999:blog-15628310.post-1163798747030064582006-11-17T16:25:00.000-05:002006-11-17T16:25:00.000-05:00If each expression is multiplied, then there shoul...If each expression is multiplied, then there should not be commas between them.<BR/><BR/>(x-a), (x-b) is not equal to <BR/>(x-a)(x-b)Mr. Donhttps://www.blogger.com/profile/03794433688939455277noreply@blogger.comtag:blogger.com,1999:blog-15628310.post-1163717099945776782006-11-16T17:44:00.001-05:002006-11-16T17:44:00.001-05:00oh...right. the variable "x" is the same as the l...oh...right. the variable "x" is the same as the letter "x". mathematically horrendous, but cute.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-15628310.post-1163717043421428922006-11-16T17:44:00.000-05:002006-11-16T17:44:00.000-05:00mike,are you telling me that (x-a)*(x-b)*(x-c)*(x-...mike,<BR/>are you telling me that (x-a)*(x-b)*(x-c)*(x-d)*...*(x-z) is zero, where a-z are integers and x is a variable? because if you are, you're crazy...please explain.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-15628310.post-1163686586108989752006-11-16T09:16:00.000-05:002006-11-16T09:16:00.000-05:00Blogger can be such a pain. Sorry about the doubl...Blogger can be such a pain. Sorry about the double post.<BR/><BR/>Answer to products: Zero. All factors are multiplied by the factor (x-x) which is zero.Anonymoushttps://www.blogger.com/profile/18153935609499338685noreply@blogger.comtag:blogger.com,1999:blog-15628310.post-1163608109114630812006-11-15T11:28:00.001-05:002006-11-15T11:28:00.001-05:00You say study of picture of postcards, of course! ...You say study of picture of postcards, of course! ;-) <BR/><BR/>But to be serious for a second, I was surprised to find out there was a study of picture postcards, nevermind there is a name for the study.Anonymoushttps://www.blogger.com/profile/18153935609499338685noreply@blogger.comtag:blogger.com,1999:blog-15628310.post-1163608101967531132006-11-15T11:28:00.000-05:002006-11-15T11:28:00.000-05:00You say study of picture of postcards, of course! ...You say study of picture of postcards, of course! ;-) <BR/><BR/>But to be serious for a second, I was surprised to find out there was a study of picture postcards, nevermind there is a name for the study.Anonymoushttps://www.blogger.com/profile/18153935609499338685noreply@blogger.comtag:blogger.com,1999:blog-15628310.post-1163605284148060862006-11-15T10:41:00.000-05:002006-11-15T10:41:00.000-05:00-(a + b + c... + w + y + z)?And Mike, if something...-(a + b + c... + w + y + z)?<BR/><BR/>And Mike, if something does not have a name how do you talk about it?Mr. Donhttps://www.blogger.com/profile/03794433688939455277noreply@blogger.com