tag:blogger.com,1999:blog-15628310.post8817166731494730843..comments2024-02-11T22:40:20.959-05:00Comments on Question of the day: I Was Late for That First Meeting to Schedule the Meeting About the ConferenceAnonymoushttp://www.blogger.com/profile/18153935609499338685noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-15628310.post-38938982471846860692010-07-27T10:21:52.928-04:002010-07-27T10:21:52.928-04:00reallyfatbloke, you're welcome.
The arrival o...reallyfatbloke, you're welcome.<br /><br />The arrival of the bus can be defined as a poisson process, while the time to arrival is on an exponential probability curve. In this case, the average (or expected time) till a bus arrives is 10 minutes. So the probability is about 9% that you will only have to wait for one minute or less for the bus to arrive.<br /><br />The chances of waiting for at least 30 minutes is about 0.5%.<br /><br />There's a good explanation of the two concepts here: http://cs.wellesley.edu/~cs199/lectures/19-exponential.html<br /><br />I know, not exactly a brain teaser, but I find it interesting.Anonymoushttps://www.blogger.com/profile/18153935609499338685noreply@blogger.comtag:blogger.com,1999:blog-15628310.post-6483384803543256472010-07-22T13:12:28.170-04:002010-07-22T13:12:28.170-04:00I love this problem, so many assumptions to make a...I love this problem, so many assumptions to make and so many ways to answer!<br /><br />I'll give one possible answer - assuming the timetable is correct and the buses arrive on time, then at any given minute a bus is either at the stop, or 9,8,7,6,5,4,3,2 or 1 minutes away from the stop - a total of ten different possibilities. So a bus being at the stop or one minute away is 2 out of ten possibilities, a 20% chance of meeting your expectation, or an 80% chance of disappointment.<br /><br />Thanks for all these great puzzles!reallyfatblokehttps://www.blogger.com/profile/17207224602405806815noreply@blogger.com