tag:blogger.com,1999:blog-15628310.post1762401061694097065..comments2024-02-11T22:40:20.959-05:00Comments on Question of the day: Roman Numeral FormulaAnonymoushttp://www.blogger.com/profile/18153935609499338685noreply@blogger.comBlogger9125tag:blogger.com,1999:blog-15628310.post-45337466564933271542016-10-08T15:56:52.354-04:002016-10-08T15:56:52.354-04:00Remove I from XI and place diagonally across =, th...Remove I from XI and place diagonally across =, thus X-I is not equal to X.Anonymoushttps://www.blogger.com/profile/04503386520130693519noreply@blogger.comtag:blogger.com,1999:blog-15628310.post-68909887455099292112015-09-14T02:31:53.646-04:002015-09-14T02:31:53.646-04:00tnx for the answer
tnx for the answer<br />jeckahttps://www.blogger.com/profile/06549581092239182595noreply@blogger.comtag:blogger.com,1999:blog-15628310.post-73148897891520284952015-09-04T17:29:51.379-04:002015-09-04T17:29:51.379-04:00I - II = -II - II = -IAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-15628310.post-9221852488458052972014-04-30T04:04:32.820-04:002014-04-30T04:04:32.820-04:00can anyone solve this equation( I - III = I) by mo...can anyone solve this equation( I - III = I) by moving one stick to get the answer? I - III = IAnonymoushttps://www.blogger.com/profile/08329266930513483532noreply@blogger.comtag:blogger.com,1999:blog-15628310.post-3571947060184373392012-07-23T01:04:02.236-04:002012-07-23T01:04:02.236-04:00IX + I = XIX + I = Xignaciohttps://www.blogger.com/profile/05073610367219211314noreply@blogger.comtag:blogger.com,1999:blog-15628310.post-6043673295549391482012-07-17T13:44:05.730-04:002012-07-17T13:44:05.730-04:00Nice!Nice!oudeishttps://www.blogger.com/profile/02798986999913350014noreply@blogger.comtag:blogger.com,1999:blog-15628310.post-35026852923979010612012-07-17T11:18:06.883-04:002012-07-17T11:18:06.883-04:00The easiest way to do this is without moving a sin...The easiest way to do this is without moving a single stick. So the answer is "0." Just turn the paper/monitor over so you're looking at the problem upside down.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-15628310.post-7560501007555093312012-07-17T05:29:13.863-04:002012-07-17T05:29:13.863-04:00XI + I = X
1. XI - I = X
(remoe vertical line fr...XI + I = X<br /><br />1. XI - I = X <br />(remoe vertical line from + to make it -)<br /><br />2. X + I = XI<br />(move I from left and appnd it to right)<br /><br />...sidAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-15628310.post-2244388388572256732012-07-16T19:32:51.106-04:002012-07-16T19:32:51.106-04:00Provided each "I" only contains a single...Provided each "I" only contains a single match, I think you can do either of the following with only one move:<br /><br />IX + I = X<br /><br />--or--<br /><br />X + I = XI<br /><br />Yes?<br /><br />(If the "I" contains three matches, the best I've got is moving two matches to produce:<br />XI = I + X)oudeishttps://www.blogger.com/profile/02798986999913350014noreply@blogger.com