tag:blogger.com,1999:blog-15628310.post114165155883590495..comments2024-02-11T22:40:20.959-05:00Comments on Question of the day: Is it worth the 25 cent toy?Anonymoushttp://www.blogger.com/profile/18153935609499338685noreply@blogger.comBlogger4125tag:blogger.com,1999:blog-15628310.post-1168551220211546242007-01-11T16:33:00.000-05:002007-01-11T16:33:00.000-05:00That's true, you would have to buy 9 ;-)That's true, you would have to buy 9 ;-)Anonymoushttps://www.blogger.com/profile/18153935609499338685noreply@blogger.comtag:blogger.com,1999:blog-15628310.post-1168546742342550292007-01-11T15:19:00.000-05:002007-01-11T15:19:00.000-05:00I don't think any store would let you purchase 1/3...I don't think any store would let you purchase 1/3 box. You'll need to but 9.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-15628310.post-1141737908766575382006-03-07T08:25:00.000-05:002006-03-07T08:25:00.000-05:00You should expect to buy 8 1/3 boxes. You will fi...You should expect to buy 8 1/3 boxes. <BR/><BR/>You will find toy #1 in box 1. You then have a 3 in 4 chance of getting a new toy in box two. Which means you should expect to buy 4/3 boxes before you get a second toy. <BR/><BR/>Once you have two different toys, the chances of gettng a new toy is 50/50. So, you should expect to buy 2 boxes before getting a new toy. <BR/><BR/>The last toy has a 1 in 4 chance of showing up, so you should expect to buy four boxes. <BR/><BR/>That gives you 1 + 4/3 + 2 + 4 = 8 1/3 boxes.Anonymoushttps://www.blogger.com/profile/18153935609499338685noreply@blogger.comtag:blogger.com,1999:blog-15628310.post-1141673350642018392006-03-06T14:29:00.000-05:002006-03-06T14:29:00.000-05:00You have a 9% chance of getting all 4 on the first...You have a 9% chance of getting all 4 on the first 4 boxes. How to translate that into number of boxes needed for 100% chance, i do not know right now. Brain fried today.Darvhttps://www.blogger.com/profile/09533799179860083881noreply@blogger.com